Torsion [Part 2]
In the previous post we examined the model of two cantilevers and came up to that constraining of warping can significantly change the deformations and stresses.
Let’s continue the same experiment with another, third cantilever.
I want to achieve the state of stresses and deformations similar to the right cantilever, but without “cheating”, with something real, that can be produced in real life. Yes, absolute rigid bodies are imaginable, they don’t exist in real life unfortunately.
No. Absolutely not. The warping of the beam hasn’t even noticed their existence here.
Simple transverse ribs don’t help I-beams with torsion.
But what can help?
Maybe more ribs?
But before we get to the answer, I want to make a lyrical digression.
closed sections
It looks like magic. Two models on the left are so “untwistable” so you may ask if I forgot to even apply any load there. But the load on all these 5 models are the same. And not only loads.
Will you be surprised if I tell you that even the sections are almost the same?
I have taken the original section and created the same one with only one difference. The thin web was divided into two even thinner webs, which were spread apart a little.
And it changed everything! This deep purple color shows us almost zero stresses. The deformations, comparing to I-sectioned beams, are… absent?
New section has the torsional constant (I.t) of 20+ times higher, which makes St Venants stresses much much lower. The stresses from magnitudes of 150..200 MPa lowered to … 6..8 MPa.
Okay, what about warping here? “Negligible” for closed sections, say books. To understand this negligibility, I want you to guess what is the difference between two models on the left. Like we did in the beginning of Torsion [Part 1] post.
Yes, the answer is still the same. One of them has the rigid element on its end. But if for open section that rigid element changed picture completely, for closed section it has done completely nothing.
Okay, reveal the magic
Look at these pictures and imagine how these small arrows can unite to some kind of pairs of forces to resist external moment.
For open sections they have no synergy for it. It is just a lot of very small counter-moments spread along the section.
For closed section it is really a team work!
And even if we cut away the parts outside of the “box”, the torsional constrain will lower only by 3%!
Okay, closed sections are for torsion. Understood. But…
Yes, let’s return to the main question of this post — how to “stiffen” the open section exposed to torsion.
We will be trying to apply different potential solutions to see which one would be closer to AM2 and further from AM1.
Yes, the only option of these three that actually worked — it is the “full box” option.
But why?
Let’s have a closer look at how the beam flanges deform at the free end.
These flanges are bending in horizontal directions, in opposite directions. They are like twisting around the vertical axis, right? But now we know what is the best way to prevent any torsion. And this is closed section.
And our “rib box” created a vertical tube (closed section!) that prevents their rotation relative to each other:
So, this is the answer.
Stiffener that can restrict torsion deformations must have a closed section.
To prove this statement, the last demonstration for today:
Two angles (L-section), forming a square box.
<>A tube, placed instead of portion of the cantilever's web — the solution that once showed me my friend Andrey Golenkin ;)
OTwo channels (U-section). Here we have two sub-options:
[ ] — closed
] [ — openAlready known for us box of longitudinal and transverse ribs
▯
Almost all of these stiffeners did their work properly. Almost. But one — that one that hasn’t created any “tube” as a stiffener.
In the next episodes
Bimoment — what does it mean?
What is 7th degree of freedom?
What is interesting about channels?
Torsion stiffness in IDEA StatiCa connection
…
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